[SQL 문제 풀이] Combine Two Tables

Can you solve this real interview question? Combine Two Tables - Table: Person +-------------+---------+ | Column Name | Type | +-------------+---------+ | personId | int | | lastName | varchar | | firstName | varchar | +-------------+---------+ personId is the primary key (column with unique values) for this table. This table contains information about the ID of some persons and their first and last names.   Table: Address +-------------+---------+ | Column Name | Type | +-------------+---------+ | addressId | int | | personId | int | | city | varchar | | state | varchar | +-------------+---------+ addressId is the primary key (column with unique values) for this table. Each row of this table contains information about the city and state of one person with ID = PersonId.   Write a solution to report the first name, last name, city, and state of each person in the Person table. If the address of a personId is not present in the Address table, report null instead. Return the result table in any order. The result format is in the following example.   Example 1: Input: Person table: +----------+----------+-----------+ | personId | lastName | firstName | +----------+----------+-----------+ | 1 | Wang | Allen | | 2 | Alice | Bob | +----------+----------+-----------+ Address table: +-----------+----------+---------------+------------+ | addressId | personId | city | state | +-----------+----------+---------------+------------+ | 1 | 2 | New York City | New York | | 2 | 3 | Leetcode | California | +-----------+----------+---------------+------------+ Output: +-----------+----------+---------------+----------+ | firstName | lastName | city | state | +-----------+----------+---------------+----------+ | Allen | Wang | Null | Null | | Bob | Alice | New York City | New York | +-----------+----------+---------------+----------+ Explanation: There is no address in the address table for the personId = 1 so we return null in their city and state. addressId = 1 contains information about the address of personId = 2.