[SQL 문제 풀이] Department Highest Salary (최고 급여 부서)

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Jun 03, 2025
[SQL 문제 풀이] Department Highest Salary (최고 급여 부서)
Department Highest Salary - LeetCode
Can you solve this real interview question? Department Highest Salary - Table: Employee +--------------+---------+ | Column Name | Type | +--------------+---------+ | id | int | | name | varchar | | salary | int | | departmentId | int | +--------------+---------+ id is the primary key (column with unique values) for this table. departmentId is a foreign key (reference columns) of the ID from the Department table. Each row of this table indicates the ID, name, and salary of an employee. It also contains the ID of their department.   Table: Department +-------------+---------+ | Column Name | Type | +-------------+---------+ | id | int | | name | varchar | +-------------+---------+ id is the primary key (column with unique values) for this table. It is guaranteed that department name is not NULL. Each row of this table indicates the ID of a department and its name.   Write a solution to find employees who have the highest salary in each of the departments. Return the result table in any order. The result format is in the following example.   Example 1: Input: Employee table: +----+-------+--------+--------------+ | id | name | salary | departmentId | +----+-------+--------+--------------+ | 1 | Joe | 70000 | 1 | | 2 | Jim | 90000 | 1 | | 3 | Henry | 80000 | 2 | | 4 | Sam | 60000 | 2 | | 5 | Max | 90000 | 1 | +----+-------+--------+--------------+ Department table: +----+-------+ | id | name | +----+-------+ | 1 | IT | | 2 | Sales | +----+-------+ Output: +------------+----------+--------+ | Department | Employee | Salary | +------------+----------+--------+ | IT | Jim | 90000 | | Sales | Henry | 80000 | | IT | Max | 90000 | +------------+----------+--------+ Explanation: Max and Jim both have the highest salary in the IT department and Henry has the highest salary in the Sales department.
Department Highest Salary - LeetCode
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내가 작성한 쿼리

MySQL, Oracle

SELECT D.name AS Department, E.name AS Employee, E.salary FROM Employee E JOIN Department D ON E.departmentId = D.id WHERE (E.departmentId, E.salary) IN ( -- 부서(departmentId)별 최고 salary 구하는 서브쿼리 SELECT departmentId, MAX(salary) FROM Employee GROUP BY departmentId );
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